Q. A body constrained to move in $Y$ direction, is subjected to a force given by $\overrightarrow{F} = \left( - 2\widehat{i} + 15\widehat{j} + 6\widehat{k} \right)$N done by this force in moving the body through a distance of 10m along $Y$ axis?

A) 190 J
B) 160 J
C) 150 J
D) 20 J
Explanation

(c) Since displacement is long the $Y$-direction, hence displacement $\overrightarrow{s} = 10\widehat{j}$.
Work done $= \overrightarrow{F} \bullet \overrightarrow{s} = \left( - 2\widehat{i} + 15\widehat{j} + 6\widehat{k} \right).10\widehat{j} = 150\ J$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.