Q. A particle moves in a circle of radius $25\ cm$ at two revolutions per second. The acceleration of the particle in $m/s^{2}$ is
A) $\pi^{2}$
B) $8\pi^{2}$
C) $4\pi^{2}$
D) $2\pi^{2}$
Explanation
(c) Since, $n = 2,\ \omega = 2\pi \times 2 = 4\pi\ rad/s^{2}$
So acceleration $= \omega^{2}r = (4\pi)^{2} \times \frac{25}{100}\ m/s^{2} = 4\pi^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.