Q. A 2 kg stone tied at the end of a string 1 m long is whirled along a vertical circle at a constant speed of $4\ ms^{- 1}$. The tension in the string has a value of 52 N when the stone is
A) At the top of the circle
B) Half way down
C) At the bottom of the circle
D) None of the above
Explanation
(c) Here, $m = 2\ kg,r = 1\ m,v = 4\ ms^{- 1}$
Tension at the bottom of the circle,
$T_{L} = mg + \frac{mv^{2}}{r}$
$= 2 \times 10 + \frac{2 \times 4^{2}}{1} = 52N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.