Q. A body of mass $m$ is projected at an angle of $45{^\circ}$ with the horizontal. If air resistance is negligible, then total change in momentum when it strikes the ground is
A) $2mv$
B) $\sqrt{2}\ mv$
C) $mv$
D) $mv/\sqrt{2}$
Explanation
(b) Change in momentum $= 2mv\sin\theta = 2mv\sin\frac{\pi}{4} = \sqrt{2}mv$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.