From an inclined plane two particles are projected with same speed at same angle $ heta$, one up and other down the plane as shown in figure. Which of the following statements $(s)$ is/are correct? [image:4_image24.emf]

Question

From an inclined plane two particles are projected with same speed at same angle $	heta$, one up and other down the plane as shown in figure. Which of the following statements $(s)$ is/are correct? [image:4_image24.emf]

Dr. Abubacker · Accepted Answer

(a) Here, $\alpha = 2	heta,\beta = 	heta$
[image:4_image114.emf]
Time of flight of $A$ is, $T_{1} = \frac{2u\sin{(\alpha - \beta)}\ }{g\ cos\ \beta}$
$= \frac{2u\sin{(2	heta - 	heta)}}{g\ cos\ 	heta} = \frac{2u}{g}tan	heta$
Time of flight of $B$ is, $T_{2} = \frac{2u\sin	heta}{g\cos	heta} = \frac{2u}{g}	an	heta$
So, $T_{1} = T_{2}$. The acceleration of both the particles is $g$ downwards. Therefore, relative acceleration between the two is zero or relative motion between the two is uniform. The relative velocity of $A$ w.r.t. $B$ is towards $AB\ $, therefore collision will take place between the two in mid air.

Q. From an inclined plane two particles are projected with same speed at same angle $\theta$, one up and other down the plane as shown in figure. Which of the following statements $(s)$ is/are correct?

Explanation

Reviewed by Dr. Abubacker

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