If $\overrightarrow{A}$ and $\overrightarrow{B}$ denote the sides of a parallelogram and its area is $\frac{1}{2}AB$($A\ $and $B$ are the magnitude of $\overrightarrow{A}$ and $\overrightarrow{B}$ respectively), the angle between $\overrightarrow{A}$ and $\overrightarrow{B}$ is

Question

Dr. Abubacker · Accepted Answer

(a) Area of parallelogram $= |A 	imes B|$
$AB\ sin	heta = \frac{1}{2}AB$
$	herefore sin	heta = \frac{1}{2},	heta = 30{^\circ}$

Q. If $\overrightarrow{A}$ and $\overrightarrow{B}$ denote the sides of a parallelogram and its area is $\frac{1}{2}AB$($A\ $and $B$ are the magnitude of $\overrightarrow{A}$ and $\overrightarrow{B}$ respectively), the angle between $\overrightarrow{A}$ and $\overrightarrow{B}$ is

Explanation

Reviewed by Dr. Abubacker

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