Q. A body of mass 1 kg thrown with a velocity of $10\ ms^{- 1}$ at an angle of $60{^\circ}$ with the horizontal. Its momentum at the highest point is
A) $2\ kg\ ms^{- 1}$
B) $3\ kg\ ms^{- 1}$
C) $4\ kg\ ms^{- 1}$
D) $5\ kg\ ms^{- 1}$
Explanation
(d) $p = mv\cos\theta$
$= 1 \times 10 \times \cos{60{^\circ}} = 10\left( \frac{1}{2} \right)kg\ ms^{- 1} = 5\ kg\ ms^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.