Q. A cyclist goes round a circular path of circumference 34.3 m in $\sqrt{22}\ $s, the angle made by him with the vertical will be
A) $45{^\circ}$
B) $40{^\circ}$
C) $42{^\circ}$
D) $48{^\circ}$
Explanation
(a) $Here,\ \ 2\pi r = 34.3 \Longrightarrow r = \frac{3403}{2\pi}\ and\ v = \frac{2\pi r}{T} = \frac{2\pi r}{\sqrt{22}}$
$Angle\ of\ banking\ \theta = \tan^{- 1}\left( \frac{v^{2}}{rg} \right) = 45{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.