Q. A body of mass $m$ is projected with a speed $u$ making an angle $\alpha$ with the horizontal. The change in momentum suffered by the body along he $y$-axis between the starting point and the highest point of its path will be
A) $mu\cos\alpha$
B) $mu\sin\alpha\ $
C) $3\ mu\sin\alpha$
D) $mu$
Explanation
(b) At the highest point, velocity along $y$-axis is zero. Therefore, change in linear momentum
$= m\left( u\sin\alpha - 0 \right) = mu\sin\alpha$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.