Q. In hydrogen atom, the electron is moving round the nucleus with velocity 2.18 $\times 10^{6}\ ms^{- 1}$ in an orbit of radius $0.528\ \mathring{\mathrm{A}}$. The acceleration of the electron is
A) 9 $\times 10^{18}\ ms^{- 2}$
B) 9 $\times 10^{22}\ ms^{- 2}$
C) 9 $\times 10^{- 22}\ ms^{- 2}$
D) 9 $\times 10^{12}\ ms^{- 2}$
Explanation
(b) Acceleration of electron
$= \frac{v^{2}}{r} = \frac{\left( 2.18 \times 10^{6} \right)^{2}}{0.528 \times 10^{- 10}} = 9 \times 10^{22}\ ms^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.