Q. The angle of projection of a projectile for which the horizontal range and maximum height are equal is
A) $\tan^{- 1}{(2)}$
B) $\tan^{- 1}{(4)}$
C) $\cot^{- 1}{(2)}$
D) $60{^\circ}$
Explanation
(b) Given, $R = H$
$\frac{u^{2}\sin{2\alpha}}{g} = \frac{u^{2}\sin^{2}\alpha}{2g}$
or $2\sin\alpha\cos\alpha = \frac{\sin^{2}\alpha}{2}$
or $\frac{\sin\alpha}{\cos\alpha} = 4$ or $\tan\alpha = 4$
$\therefore\ \ a = \tan^{- 1}{(4)}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.