If the radius of curvature of the path of two particles of same masses are in the ratio $1\ :2$, then in order to have constant centripetal force, their velocity, should be in the ratio of

Question

Dr. Abubacker · Accepted Answer

(d) The centripetal force, $F = \frac{mv^{2}}{r} \Rightarrow r = \frac{mv^{2}}{F}$
$	herefore r \propto v^{2}$ or $v \propto \sqrt{r}$ [If $m$ and $F$ are constant]
$\Rightarrow \frac{v_{1}}{v_{2}} = \sqrt{\begin{array}{r}
\frac{r_{1}}{r_{2}} \
\ 
\end{array}} = \sqrt{\begin{array}{r}
\frac{1}{2} \
\ 
\end{array}}$

Q. If the radius of curvature of the path of two particles of same masses are in the ratio $1\ :2$, then in order to have constant centripetal force, their velocity, should be in the ratio of

Explanation

Reviewed by Dr. Abubacker

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