A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of $60\ kmh^{- 1}$ and at a height of 490 m. At the time of dropping the bomb, how far the aeroplane should be from the enemy post so that the bomb may directly hit the target?

Question

Dr. Abubacker · Accepted Answer

(b) $t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 	imes 490}{9.8}} = \sqrt{100} = 10\ s$
$x = vt = \left( 60 	imes \frac{5}{18} ight)ms^{- 1} 	imes 10\ s = \frac{500}{3}m$

Q. A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of $60\ kmh^{- 1}$ and at a height of 490 m. At the time of dropping the bomb, how far the aeroplane should be from the enemy post so that the bomb may directly hit the target?

Explanation

Reviewed by Dr. Abubacker

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