Q. Two paper screens $A$ and $B$ are separated by a distance of 200 m. A bullet pierces $A$ and then $B$. The hole in $B$ is 40 cm below the hole in $A$. If the bullet is travelling horizontally at the time of hitting $A$, then the velocity of the bullet at $A$ is

A) $200\ ms^{- 1}$
B) $400\ ms^{- 1}$
C) $600\ ms^{- 1}$
D) $700\ ms^{- 1}$
Explanation

(d) $200 = ut$
[image:4_image122.jpeg]
or $t = 200/u$
Also, $\frac{40}{100} = \frac{1}{2} \times 9.8\left( \frac{200}{u} \right)^{2}$
On solving $u = 700\ ms^{- 1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.