Q. If the range of a gun which fires a shell with muzzle speed $V$ is $R$, then the angle of elevation of the gun is
A) $\cos^{- 1}\left( \frac{V^{2}}{Rg} \right)$
B) $\cos^{- 1}\left( \frac{gR}{V^{2}} \right)$
C) $\frac{1}{2}\left( \frac{V^{2}}{Rg} \right)$
D) $\frac{1}{2}\sin^{- 1}\left( \frac{gR}{V^{2}} \right)$
Explanation
(d) $R = \frac{\upsilon^{2}\sin{2\theta}}{g} \Rightarrow \theta = \frac{1}{2}\sin^{- 1}\left( \frac{gR}{\upsilon^{2}} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.