Q. An athlete completes one round of a circular track of radius 10$\ m$ in 40$\ sec.$ The distance covered by him in 2 $\min$ 20 $\sec$ is

A) 70 $m$
B) 140$\ m$
C) 110$\ m$
D) 220$\ m$
Explanation

(d) Time period = 40$\ sec$
No. of revolution = $\frac{Total\ time}{Time\ period} = \frac{140\ sec}{40\ sec} = 3.5\ Rev.$
So, distance $= 3.5 \times 2\pi R = 3.5 \times 2\pi \times 10 = 220m.$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.