Four concurrent coplanar forces in newton are acting at a point and keep it in equilibrium figure. Then values of $F$ and $ heta$ are [image:4_image30.emf]

Question

Four concurrent coplanar forces in newton are acting at a point and keep it in equilibrium figure. Then values of $F$ and $	heta$ are [image:4_image30.emf]

Dr. Abubacker · Accepted Answer

(d) In equilibrium position along $y$-direction
2 sin 60${^\circ}$ $= \sqrt{3} + F\cos	heta$
or $2 	imes \frac{\sqrt{3}}{2} = \sqrt{3} + F\cos	heta$ or $F\cos	heta = 0$
As $F 
eq 0$
$	herefore\ \cos	heta = 0$ or $	heta = 90{^\circ}$
Along $x$-direction, $F\ \sin 90{^\circ} = 1 + 2\cos 60{^\circ}$
$= 1 + 2 	imes \frac{1}{2}$
$F = 2$N

Q. Four concurrent coplanar forces in newton are acting at a point and keep it in equilibrium figure. Then values of $F$ and $\theta$ are

Explanation

Reviewed by Dr. Abubacker

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