Q.
Three forces of magnitudes 6N, 6N and $\sqrt{72}$ N at a corner of a cube along three sides as shown in figure. Resultant of these forces is
A) 12 N along $OB$
B) 18 N along $OA$
C) 18 N along $OC$
D) 12 N along $OE$
Explanation
(d) The resultant of 5 N along $OC$ and 5 N along $OA$ is
$R = \sqrt{6^{2} + 6^{2}}$
$= \sqrt{72}\ $N along $OB$
The resultant of $\sqrt{72}$ N along $OB$ and $\sqrt{72}$ N along $OG$ is
$R^{'} = \sqrt{72 + 72} = 12$N along $OE$.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.