(d) $Given,\ m = 1 \times 10^{- 3}\ kg,\ \omega = 1\ rad\ s^{- 1}\ and\ r = 1m$ Hence, centrifugal force $= m\omega^{2}r = 10^{- 3}N$ $1N = 10^{5}\ dyne$ $\therefore Centrifugal\ force = 100\ dyne$
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Ph.D. in Physics with 19+ years of teaching experience.