Q. A mass of 100 g is tied to one end of string 2 m long. The body is revolving in a horizontal circle making a maximum of 200 revolutions/min. The other end of the string is fixed at the centre of the circle of revolution. The maximum tension that the string can bear is approximately
A) $8.76$ N
B) 8.94 N
C) 89.42 N
D) 87.64 N
Explanation
(d) Maximum tension, $F = mr\omega^{2} = mr4\pi^{2}v^{2}$
$= 0.1 \times 2 \times 4 \times \pi^{2} \times (200/60)^{2} = 87.64\ $N
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.