Q. A body is fired vertically upward. At half the maximum height, the velocity of the body is $10\ m/s$. The maximum height raised by the body is
A) $0\ m$
B) $10\ m$
C) $15\ m$
D) $20\ m$
Explanation
(b) $v^{2} = u^{2} + 2as$ …(i)
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At $B,\ u = 10\ m/s$
at max. height, $\upsilon = 0$
$a = - 10\ m/s^{2};s = h/2$
From equation (i)
$0 = (10)^{2} + 2( - 10)h/2 \Rightarrow h = 10\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.