(b) On a circular path in completing one turn, the distance traveled is $2\pi r$ while displacement is zero.
$Hence,\ \ \ \ average\ velocity = \frac{displacement}{time\ interval} = \frac{0}{t} = 0$
$Average\ speed = \frac{distance\ }{time\ interval}$
$= \frac{2\pi r}{t} = \frac{2 \times 3.14 \times 100}{62.8} = 10{\ ms}^{- 1}\ $