Q. A helicopter is flying horizontally at an altitude of 2 km with a speed of $100\ ms^{- 1}$. A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is $(g = 10\ ms^{- 2})$

A) 2 km
B) 0.2 km
C) 20 km
D) 4 km
Explanation

(a) $t = \sqrt{\frac{2 \times 2000}{10}} = \sqrt{400} = 20\ s$
$x = 100ms^{- 1} \times 20s = 2000\ m = 2km$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.