Two bodies are projected from ground with equal speed ${20\ ms}^{- 1}$ from the same position in the same vertical plane to have equal range but at different angles above the horizontal. If one of the angle is $30{^\circ}$ the sum of their maximum heights is $(assume\ g = \ {10\ ms}^{- 2})$

Question

Dr. Abubacker · Accepted Answer

(d) Maximum height attained is given by
$h_{\max} = \frac{u^{2}}{2g}$
$Given,\ u = 20{ms}^{- 1}$
$h_{\max} = \frac{(20)^{2}}{2 	imes 10} = 20m$
For the second body also $h_{\max} = 20m$
$	herefore Sum\ of\ maximum\ height = 20m$+20m=40m

Q. Two bodies are projected from ground with equal speed ${20\ ms}^{- 1}$ from the same position in the same vertical plane to have equal range but at different angles above the horizontal. If one of the angle is $30{^\circ}$ the sum of their maximum heights is $(assume\ g = \ {10\ ms}^{- 2})$

Explanation

Reviewed by Dr. Abubacker

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