Q. Neglecting the air resistance, the time of flight of a projectile is determined by
A) $U_{vertical}$
B) $U_{horizontal}$
C) $U = U_{vertical}^{2} + U_{horizontal}^{2}$
D) $U = U\left( U_{vertical}^{2} + U_{horizontal}^{2} \right)^{1/2}$
Explanation
(a) Time of flight $= \frac{2u\sin\theta}{g} = \frac{2u_{y}}{g} = \frac{2 \times u_{vertical}}{g}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.