Q. A cyclist goes round a circular path of circumference $34.3\ m$ in $\sqrt{22}\ sec.$ the angle made by him, with the vertical, will be
A) $45{^\circ}$
B) $40{^\circ}$
C) $42{^\circ}$
D) $48{^\circ}$
Explanation
(a) $2\pi r = 34.3 \Rightarrow r = \frac{34.3}{2\pi}$ and $v = \frac{2\pi r}{T} = \frac{2\pi r}{\sqrt{22}}$
Angle of banking $\theta = \tan^{- 1}\ \left( \begin{array}{r}
\frac{v^{2}}{rg} \\
\
\end{array} \right) = 45{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.