Q. In above question, if the centripetal force $F$ is kept constant but the angular velocity is doubled, the new radius of the path (original radius $R$) will be
A) $2R$
B) $R/2$
C) $R/4$
D) $4R$
Explanation
(c) $F = m\omega^{2}R\ \therefore R \propto \frac{1}{\omega^{2}}$ ($m$ and $F$ are constant)
If $\omega$ is doubled then radius will become $1/4$ times i.e. $R/4$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.