Q. A cyclist is travelling with velocity $v$ on a banked curved road of radius R. The angle $\theta$ through which the cyclist leans inwards is given by
A) $\tan{\theta = \frac{Rg}{v^{2\ }}}$
B) $\tan{\theta = \ v^{2}\ Rg}$
C) $\tan{\theta = \frac{v^{2}g}{R}}$
D) $\tan{\theta = \frac{v^{2}}{Rg}}$
Explanation
(d) $R\cos{\theta = mg\ \ldots(i)}$
$R\sin{\theta = \frac{{mv}^{2}}{R}\ldots(ii)}$
From, Eqs. (i) and (ii) we get
$\therefore\ \tan{\theta = \frac{v^{2}}{Rg}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.