An artillery piece which consistently shoots its shells with the same muzzle speed has a maximum range R. To hit a target which is $\frac{R}{2}$ from the gun and on the same level, the elevation angle of the gun should be

Question

Dr. Abubacker · Accepted Answer

(a) $R_{\max} = R = \frac{u^{2}}{g}$
$\Longrightarrow u^{2} = Rg$
$Now,\ as\ range = \frac{u^{2}sin2	heta}{g}$
$then\frac{R}{2} = \frac{Rgsin2	heta}{g}$
$\Longrightarrow sin2	heta = \frac{1}{2} = sin30{^\circ} \Longrightarrow 	heta = 15{^\circ}$

Q. An artillery piece which consistently shoots its shells with the same muzzle speed has a maximum range R. To hit a target which is $\frac{R}{2}$ from the gun and on the same level, the elevation angle of the gun should be

Explanation

Reviewed by Dr. Abubacker

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