Q. For a body moving in a circular path, a condition for no skidding if $\mu$ is the coefficient of friction, is
A) $\frac{mv^{2}}{r} \leq \mu mg$
B) $\frac{mv^{2}}{r} \geq \mu mg$
C) $\frac{v}{r} = \mu g$
D) $\frac{mv^{2}}{r} = \mu mg$
Explanation
(a) The value of frictional force should be equal or more than required centripetal force. i.e. $\mu mg \geq \frac{mv^{2}}{r}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.