Q. A body of mass $m$ is moving in a circle of radius $r$ with a constant speed $v$. The force on the body is $\frac{mv^{2}}{r}$ and is directed towards the centre. What is the work done by this force in moving the body over half the circumference of the circle
A) $\frac{mv^{2}}{r} \times \pi r$
B) Zero
C) $\frac{mv^{2}}{r^{2}}$
D) $\frac{\pi r^{2}}{mv^{2}}$
Explanation
(b) Work done by centripetal force is always zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.