Q. If a cycle wheel of radius 4 $m$ completes one revolution in two seconds. Then acceleration of a point on the cycle wheel will be
A) $\pi^{2}m/s^{2}$
B) $2\pi^{2}m/s^{2}$
C) $4\pi^{2}m/s^{2}$
D) $8\pi m/s^{2}$
Explanation
(c) Centripetal acceleration $= 4\pi^{2}n^{2}r = 4\pi^{2}\left( \frac{1}{2} \right)^{2} \times 4 = 4\pi^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.