(a) $T_{\max} = m\omega_{\max}^{2}r + mg\ \Rightarrow \frac{T_{\max}}{m} = \omega^{2}r + g$ $\Rightarrow \frac{30}{0.5} - 10 = \omega_{\max}^{2}r \Rightarrow \omega_{\max} = \sqrt{\frac{50}{r}} = \sqrt{\frac{50}{2}} = 5\ rad/s$
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