(b) $cos\theta = \frac{\left( \widehat{k} \right).(\widehat{i} + \widehat{j} + \sqrt{2}\widehat{k})}{1\sqrt{1^{2} + 1^{2}\left( \sqrt{2} \right)^{2}}}$ or $cos\theta = \frac{\sqrt{2}}{2} = \frac{1}{\sqrt{2}}$ or $\theta = 45{^\circ}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.