Q. The earth moves round the sun in a near circular orbit of radius $1.5 \times 10^{11}$ m. Its centripetal acceleration is
A) $1.5 \times 10^{- 3}\ m/s^{2}$
B) $3 \times 10^{- 3}\ m/s^{2}$
C) $6 \times 10^{- 3}\ m/s^{2}$
D) $12 \times 10^{- 3}\ m/s^{2}$
Explanation
(c) Centripetal acceleration, $a_{c} = w^{2}R$
$= \frac{(2\pi)^{2} \times 1.5 \times 10^{11}}{(365 \times 86400)^{2}} = 6 \times 10^{- 3}ms^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.