(d) Centripetal acceleration, $a = \omega^{2}r$ $= 4\pi^{2}n^{2}r = 4\pi^{2}\left( \frac{1}{2} \right)^{2} \times 100$ $\pi^{2} \times 100{ms}^{- 2} = 985.9{ms}^{- 2}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.