Q. A particle covers $50\ m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed
A) $100\ m$
B) $150\ m$
C) $200\ m$
D) $250\ m$
Explanation
(c) $R = \frac{u^{2}\sin{2\theta}}{g} = R \propto u^{2}.\ $So if the speed of projection doubled, the range will becomes four times,
$i.e.,$ $4 \times 50 = 200\ m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.