Q.
Consider a disc rotating in the horizontal plane with a constant angular speed $\omega$ about its centre $O$. The disc has a shaded region on one side of the diameter and an unshanded region on the other side as shown in the figure. When the disc is in the orientation as shown, two pebbles $P$ and $Q$ are simultaneously projected at an angle towards $R$. The velocity of projection is in the $y - z$ plane and is same for both pebbles with respect to the disc. Assume that (i) they land back on the disc before the disc has completed $\frac{1}{8}$ rotation. (ii) their range is less than half the disc radius, and (iii) $\omega$ remains constant throughout. Then
A) $P$ lands in the shaded region and $Q$ in the unshaded region
B) $P$ lands in the unshaded region and $Q$ in the shaded region
C) Both $P$ and $Q$ land in the unshaded region
D) Both $P$ and $Q$ land in the shaded region
Explanation
(a) [image:4_image141.emf]
To reach the unshaded portion particle $P$ needs to travel horizontal range greater than $R\sin{45{^\circ}}$ or $(0.7\ R)$ but its range is less than $\frac{R}{2}$. So it will fall on shaded portion
$Q$ is near to origin, its velocity will be nearly along $QR$ so its will fall in unshaded portion
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.