Work done when a force, $\overrightarrow{F} = (\widehat{i} + 2\widehat{j} + 3\widehat{k})$N acting on a particle takes it from the point ${\overrightarrow{r}}_{1} = (\widehat{i} + \widehat{j} + \widehat{k})$m to the point ${\overrightarrow{r}}_{2} = (\widehat{i} + \widehat{j} + 2\widehat{k})$

Question

Dr. Abubacker · Accepted Answer

(b) Displacement , $\overrightarrow{r} = {\overrightarrow{r}}_{2} - {\overrightarrow{r}}_{1}$
$= \left( \widehat{i} - \widehat{j} + 2\widehat{k} ight) - \left( \widehat{i} - \widehat{j} + 2\widehat{k} ight) = - 2\widehat{i} + \widehat{k}$
$	herefore$ workdone, $W = \overrightarrow{F} \bullet \overrightarrow{r}$=($\widehat{i} + 2\widehat{j} + 3\widehat{k}$)$\bullet \left( - 2\widehat{j} + \widehat{k} ight) = - 1\ $J

Q. Work done when a force, $\overrightarrow{F} = (\widehat{i} + 2\widehat{j} + 3\widehat{k})$N acting on a particle takes it from the point ${\overrightarrow{r}}_{1} = (\widehat{i} + \widehat{j} + \widehat{k})$m to the point ${\overrightarrow{r}}_{2} = (\widehat{i} + \widehat{j} + 2\widehat{k})$

Explanation

Reviewed by Dr. Abubacker

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