Q. A body is projected horizontally with speed $20\ ms^{- 1}$. The approximate displacement of the body after 5 s is
A) 80 m
B) 120 m
C) 160 m
D) 320 m
Explanation
(c) $x = 20 \times 5 = 100m$
$y = \frac{1}{2} \times 10 \times 5 \times 5 = 125m$
$r = \sqrt{100^{2} + 125^{2}} = 160m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.