Q.
A man 80 kg is supported by two cables as shown in the figure. Then the ratio of tensions $T_{1}$ and $T_{2}$ is
A) 1:1
B) 1:$\sqrt{3}$
C) $\sqrt{3}:1$
D) 1:3
Explanation
(c) From figure in equilibrium position
$T_{1}\sin 30{^\circ} = T_{2}\sin 60{^\circ}$
or $T_{1} \times \frac{1}{2} = T_{2} \times \frac{\sqrt{3}}{2}$
or $\frac{T_{1}}{T_{2}} = \sqrt{3}$
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.