Q. A particle is moving in a circular path with a constant speed $v$. If $\theta$ is the angular displacement, then starting from $\theta = 0{^\circ}$, the maximum and maximum changes in the momentum will occur, when value of $\theta$ is respectively

A) 45${^\circ}$ and 90${^\circ}$
B) 90${^\circ}$ and 180${^\circ}$
C) 180${^\circ}$ and 360${^\circ}$
D) 90${^\circ}$ and 270${^\circ}$
Explanation

(c) When $\theta = 180{^\circ}$, the particle will be at diametrically opposite point, where its velocity is opposite to the initial directions of motion. The change in momentum $= mv - ( - mv) = 2mv$ (maximum). When $\theta = 360{^\circ}$, the particle is at the initial position with momentum $m$. Change in momentum $mv - mv = 0$ (minimum)

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.