(c) Tension, $T = \frac{mv^{2}}{r} + mg\cos\theta$ $For,\ \theta = 30{^\circ},\ T_{1} = \frac{mv^{2}}{r} + mg\cos{30{^\circ}}$ $\theta = 60^{o},T_{2} = \frac{mv^{2}}{r} + mg\cos 60^{o}\therefore T_{1} > T_{2}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.