Q. A tube of length $L$ is filled completely with an incompressible liquid of mass $M$ and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity $\omega$. The force exerted by the liquid at the other end is
A) $\frac{ML\omega^{2}}{2}$
B) $ML\omega^{2}$
C) $\frac{ML\omega^{2}}{4}$
D) $\frac{ML^{2}\omega^{2}}{2}$
Explanation
(a) The centre of gravity of other tube will be at length $L/2$
So radius $r = L/2$
Centripetal force, $= M\ r\ \omega^{2} = M(L/2)\omega^{2} = ML\omega^{2}/2$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.