(d) $B_{x} = 10 - 6 = 4$ and $B_{y} = 9 - 6 = 3$ so, $B = \left( B_{x}^{2} + B_{y}^{2} \right)^{1/2}$=$\sqrt{4^{2} + 3^{2}} = \sqrt{16 + 9}$ $= \sqrt{25} = 5$
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Ph.D. in Physics with 19+ years of teaching experience.