Q. The $X$ and $Y$ components of vector $\overrightarrow{A}$ have numerical values 6 and 6 respectively and that of $(\overrightarrow{A} + \overrightarrow{B})$ have numerical values 10 and 9. What is the numerical value of $\overrightarrow{B}?$

A) 2
B) 3
C) 4
D) 5
Explanation

(d) $B_{x} = 10 - 6 = 4$ and $B_{y} = 9 - 6 = 3$
so, $B = \left( B_{x}^{2} + B_{y}^{2} \right)^{1/2}$=$\sqrt{4^{2} + 3^{2}} = \sqrt{16 + 9}$
$= \sqrt{25} = 5$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.