Q. A plumb line is suspended from a ceiling of a car moving with horizontal acceleration of$a$. What will be the angle of inclination with vertical?
A) $tan^{- 1}\left( \frac{a}{g} \right)$
B) $tan^{- 1}\left( \frac{g}{a} \right)$
C) $cas^{- 1}\left( \frac{a}{g} \right)$
D) $cas^{- 1}\left( \frac{g}{a} \right)$
Explanation
(a) Let the angle from the vertical be$\theta$. The diagram showing the different forces is given
[image:4_image146.emf]
$Form\ the\ figure,\ \ \tan{\theta = \frac{a}{g}}$
$\theta = tan^{- 1}\frac{a}{g}\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.