Q. A stone thrown at an angle $\theta$ to the horizontal a projectile makes an angle $\pi/4$ with the horizontal, then its initial velocity and angle of projection are, respectively

A) $\frac{\sqrt{2h\sin\theta}}{g}$
B) $\frac{2\sqrt{2h\sin\theta}}{g}$
C) $2\sqrt{\frac{2h}{g}}$
D) $\sqrt{\frac{2h}{g}}$
Explanation

(c) Here, $h = \frac{{u^{2}\sin^{2}}\theta}{2g}\ or\ \sqrt{\frac{2h}{g}} = \frac{u\ sin\ \theta}{g}$
Time of flight, $T = \frac{2u\ sin\ \theta}{g} = 2\sqrt{\frac{2h}{g}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.