(c) Here, $h = \frac{{u^{2}\sin^{2}}\theta}{2g}\ or\ \sqrt{\frac{2h}{g}} = \frac{u\ sin\ \theta}{g}$ Time of flight, $T = \frac{2u\ sin\ \theta}{g} = 2\sqrt{\frac{2h}{g}}$
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Ph.D. in Physics with 19+ years of teaching experience.