Q. A particle moves in a circle of radius $5\ cm$ with constant speed and time period $0.2\ \pi s$. The acceleration of the particle is
A) $5\ m/s^{2}$
B) $15\ m/s^{2}$
C) $25\ m/s^{2}$
D) $36\ m/s^{2}$
Explanation
(a) $a = \omega^{2}R = \left( \frac{2\pi}{0.2\pi} \right)^{2}\left( 5 \times 10^{- 2} \right) = 5\ m/s^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.