Q. An aircraft executes a horizontal loop with a speed of $150\ m/s$ with its wings banked at an angle of $12{^\circ}$. The radius of the loop is $(g = 10\ m/s^{2},\tan{12{^\circ} = 0.2126}\ )$

A) $10.6\ km$
B) $9.6\ km$
C) $7.4\ km$
D) $5.8\ km$
Explanation

(a) The angle of banking, $\tan\theta = \frac{v^{2}}{rg}$
$\Rightarrow \tan 12^{o} = \frac{(150)^{2}}{r \times 10} \Rightarrow r = 10.6 \times 10^{3}m = 10.6\ km$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.