(b) Here, $r = 100\ m,t = 62.8$ s In one circular loop, displacement = 0 $\therefore\ \ $Velocity=0 Distance traveled =2$\pi r$ $\therefore$ Speed $= \frac{2\pi r}{t} = \frac{2.14 \times 100}{62.8} = 10\ ms^{- 1}$
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